6r^2-37r-35=0

Solution for 6r^2-37r-35=0 equation:

6r^2-37r-35=0

a = 6; b = -37; c = -35;
Δ = b2-4ac
Δ = -372-4·6·(-35)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-47}{2*6}=\frac{-10}{12}
=-5/6
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+47}{2*6}=\frac{84}{12}
=7
$